A ball is dropped from the top of a tower 40m high. What is its velocity when it has covered 20m? (g = 10m/s2)
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Answer:
V = 28.01 m/s
Explanation:
The total height of the tower is 40 m.
Lets total time be = t
Initial velocity u= 0
Case 1: whats the velocity when the body at 20 m. High
From the formula
V^2 - u^2 =2 * a* s
V^2 - 0^2 = 2*9.81* 20
V^2 = 392.4
V= √392.4
V = 19.809 m/s
Case2 :velocity when the ball hits the ground
From
V^2 - u^2 =2 * a* s
V^2 - 0^2 = 2 *9.81* 40
V^2 = 784.8
V=√784.8
V = 28.01 m/s
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