Question

a ball is dropped from the top of a tower 40m high, what is it's velocity when it has covered 20m ? What would be it's velocity when it hits the ground​

Answer 1

Answer:

the velocity when it was covered 20 m = 20m/s

the velocity at hits the ground = 28.28 m/s

Explanation:

h =40 m

the velocity of ball at hits the ground v= √2gh = √2×10×40 =√800 = 28.28 m/s

the velocity when it was covered 20m

v^2-u^2 =2as

v^2- 0^2 =2×10×20

v=20m/s