Physics, asked by chandan4315, 9 months ago

a ball is dropped from the top of a tower.it bounces from the groundland rises to a certain height draw the velocity time graphs of the motion of the ball​

Answers

Answered by IonicYadav
1

Answer:

We get v

We get v 2

We get v 2 =2as Since u=0

We get v 2 =2as Since u=0Clearly the graph will be parabolic.

We get v 2 =2as Since u=0Clearly the graph will be parabolic.The velocity will be negative while the ball falls while it will be positive when it bounces back i.e. they will have opposite direction, also the maximum height will be

We get v 2 =2as Since u=0Clearly the graph will be parabolic.The velocity will be negative while the ball falls while it will be positive when it bounces back i.e. they will have opposite direction, also the maximum height will be 2

We get v 2 =2as Since u=0Clearly the graph will be parabolic.The velocity will be negative while the ball falls while it will be positive when it bounces back i.e. they will have opposite direction, also the maximum height will be 2d

We get v 2 =2as Since u=0Clearly the graph will be parabolic.The velocity will be negative while the ball falls while it will be positive when it bounces back i.e. they will have opposite direction, also the maximum height will be 2d

We get v 2 =2as Since u=0Clearly the graph will be parabolic.The velocity will be negative while the ball falls while it will be positive when it bounces back i.e. they will have opposite direction, also the maximum height will be 2d

Answered by devlok
0

Answer:hey

I got your problem.

।   (v)

।.

।  .

।    .

।       .                

।            .

।                  .

!o--------------------------------------------------(t)-.

।                            .                           .

।                                  .                .

।                                        .

।    

Explanation: join all dot.

Similar questions