Question

A ball is dropped from the top of a tower of height 80m .At the same time another ball is projected horizontally from the tower.Find the time taken by both the balls to reach the ground. qquad ( Take g=10ms^(-2))

Answer 1

Explanation:

Vertical Velocity of both balls initially is zero

So,s=ut+1/2at²

80=s=0+1/2×10×t²

16=t²

t²=16

t=4 sec for both balls