Question

a ball is dropped from the top of a tower of of height h and it travels a distance 15h/64 in the last second . the time of journey and height of tower is​

Answer 1

Answer:

For 1^st h2 fall h2 = 0t1 + 12gt^21 [ from S = mu t + 12gt^2] h2 = 12gt^21 hg = t^21....(1) Also we know V = 0 + gt1 V = gt1 For 2^nd h2 fall h2 = (gt1)t2 ...