Question

A ball is dropped from the top of tower 40m what is it velocity when it has covered 20m

Answer 1

Answer:

1. When ball fall from 40m and cover 20m…. All the potential energy convert into kinetic energy then

1/2 mv^2 = mgh

V = root of 2gh

Here h = 40 - 20 = 20

V= √(2*10*20)

V= 20m/s

2. When it fall on ground

h=40m

V= √(2*10*40)

V=28.28m/s

You can use g = 9.81 instead of 10. But calculation purpose i use 10 m/s^2

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