Question

A ball is dropped from the tower of height 100 m.Calculate time taken by object to reach ground and what is the velocity when it strikes the ground

Answer 1

Explanation:

u=0

h=100m

using equation

h=ut+1/2gt^2

100=0+1/2*10*t^2

t=100*2/10

t=4√5 seconds

Answer 2

Answer:

Heya.......

Here's ur answer :

Given:

Distance covered (s) = height = 100 m

time taken (t) = ?

g = 10 m/s^2

initial velocity = u = 0 m/s

we have,

s = ut + 1/2 (gt^2)

=> 100 = 0*t + 1/2(10 t^2)

=> 100 = 1/2(10t^2)

=> t^2 = 100*2/10

=> t^2 = 20

=> t = √20

=>> t = 4.47 sec

Hence, the time taken to reach the ground is 4.47 sec.

Now,

By first kinematic equation :

v = u + at = u + gt

=> v = 0 + 10*4.47

=> v = 44.7 m/s

Hence, the velocity of object when it strikes the ground is 44.7 m/s

❤Hope it helps❤!!... ✌