A ball is dropped froma height h,the distance travelled in last three second is equals to
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Hii!!
The distance covered in first 3 second
s=12s=12gt2gt2
=12=12×10×32×10×32
=45=45
If the ball takes 'n' second to fall to ground . The distance covered in nthnth second
sn=u+g2sn=u+g2(2n−1)(2n−1)
=0+102=0+102(2n−1)(2n−1)
=10n−5=10n−5
Therefore 45=10n−545=10n−5
n=5n=5
Therefore h=12h=12gt2gt2
=12=12×10×25×10×25
=125m
Hope it works!!!
The distance covered in first 3 second
s=12s=12gt2gt2
=12=12×10×32×10×32
=45=45
If the ball takes 'n' second to fall to ground . The distance covered in nthnth second
sn=u+g2sn=u+g2(2n−1)(2n−1)
=0+102=0+102(2n−1)(2n−1)
=10n−5=10n−5
Therefore 45=10n−545=10n−5
n=5n=5
Therefore h=12h=12gt2gt2
=12=12×10×25×10×25
=125m
Hope it works!!!
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