A ball is dropped horizontally and at the same time another ball is dropped vertically from the top of a
tower,
(a) Will both the balls reach the ground at the same time? [1]
(b) Will both the balls strike the ground with same velocity?
Answers
Explanation:
(b) Will both the balls strike the ground with same velocity?
Answer:
If you ensure that when throwing the ball horizontally, the ball does not have any velocity in the vertical component- then both balls will fall at the same velocity at every individual component of time and will therefore hit the ground at equal velocity in the ‘vertical’ component. This because acceleration due to gravity acts only downwards and does not affect the horizontal velocity of the ball since forces can only act upon against or with each other if they’re in the same coordinate frame (in this case the forces are- mass times gravity and the force with which the ball was thrown. Both forces are in different coodinates and therefore cannot effect each other). However the horizontal velocities of the balls will never be the same since the ball dropped vertically has no initial horizontal velocity. Even if the balls were dropped from very high height and significant air resistance acts upon them that the horizontal velocity of the first ball reduces , it will always be greater than the ball which was ‘just dropped’ and has zero horizontal velocity. Infact hypothetically- if the balls are dropped from an increasing amount of height and encounters an increasing amount of air resistance, its horizontal velocity will tend to zero. but it will only reach zero at infinity height. At which point the horizontal velocity and vertical velocity of both balls will finally be equal. However you will be dead because its going take them an infinite amount of time to hit the ground, they will burn up due to friction with the air before they fall on to the ground
full explanation ;);)
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