Question

A ball is dropped into a pond from the height of 44.1 m splash of sound is heard 3.13 second after the ball is dropped determine the velocity of the sound in air?

Answer 1

so total time to reach the well lower most point is

by the formula s=ut +1/2 gt$^2$

$44.1=0 + \frac{1}{2} × 9.8 × t^2$

$\frac{44.1×2}{9.8} = t^2$

$9 = t^2$

$\sqrt{9} = \sqrt{t^2}$

$t = 3$

so time take to reach there is 3 sec now the time taken by sound to reach the ears is

3.13s - 3s = 0.13s

$speed=\frac{distance}{time}$

$speed = \frac{44.1}{0.13}$

$speed = 339.23 \:ms^{-1}$

Answer 2

Answer:

thank youh have a nice day