A ball is dropped off a high cliff, and 2s later another ball is thrown vertically downwards with an initial speed of 30m/s. How long will it take the second ball to overtake the first?
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Explanation:1st Ball:
d1 = Vo*t + 0.5g*t^2
d1 = 0 + 4.9*2^2 = 19.6 m in 2 seconds
2nd Ball:
d2 = d1 + 19.6 m
Vo*t + 0.5g*t^2 = 4.9t^2 + 19.6
30t + 4.9t^2 - 4.9t^2 = 19.6
30t = 19.6
t = 0.6533 s. To overtake the 1st ball.
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