Question

A ball is dropped on a floor from a height 20m. Every time the ball rebounds, its speed after collision becomes 0.8 times of its speed before collision. Then, the average speed of the ball until it comes to rest is ___________ m/s. [Take g=10 ]

Answer 1

Answer. this is your answer . hope this helped

Answer 2

Answer:

The average speed of the ball until it comes to rest is  341m/s^2.

Explanation:

Collision means sudden force coming together in direct contact with two bodies. For example hammer and a ball.

Velocity means the shake or movement of the objects.

Here we have to find the average speed of the ball till it comes to rest.

Therefore,

$g=10m/s^{2}$

v₁=√2gh1 = √2×10×20 =20m/s          

v₂ =√2gh2 = √2×10×10 =10 √2m/s (opposite)

Now here change in velocity,

ㅿv= v₂-v₁= 10 $\sqrt{2}$ -(-20)

= 14.1 + 20 =34.1 m/s (upward)

a= $\frac{Δv}{Δt}$= 34.1/0.1 = 341$m/s^{2}$ (upward)

Hence,

The average speed of the ball, until it comes to rest, is = 341$m/s^{2}$proved.

To learn more about velocity, visit:

https://brainly.in/question/11504533

To learn more about collision, visit:

https://brainly.in/question/7481363

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