A ball is dropped on the floor from a height of 10 m .It rebounds to a height of 2.5 m .If the ball is the contact with the floor for 0.01 seconds,then the average acceleration during contact is nearly how much.
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the same question is present in 9th class 2nd lesson
s=ut+1/2at^2
based on this formula the answer is 5m/s
the average acceleration =5m/s
s=ut+1/2at^2
based on this formula the answer is 5m/s
the average acceleration =5m/s
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