A ball is dropped on the floor from a height of 10m.It rebounds to a height of 2.5m.If the ball is in contact with floor for 0.01s.Then average acceleration during contact is
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Average acc. = total velocity/ total time ; √2gh(10) -√2gh(2.5) =5√2(total velocity) ; total time=0.01s Average acc = 500√2
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