A ball is dropped on top of a building. a) What is the initial velocity of the ball? b) What is the height of the building if the ball reaches the floor in 5 s ? c) What is the velocity of the ball just before it hits the ground?
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Answer:
Motion Chapter
Explanation:
u = initial velocity = 0 m/s
v = final velocity = ?m/s
a = g = acceleration due to gravity = 9.8 m/s²
t = time interval = 5 s
s = displacement = ? m
Calculate the displacement using the following kinematic equation.
s = ut + ½at²
Since u = 0, the equation can be rewritten as:
s = ½at²
s = 0.5 × 9.8 m/s² × (5 s)² = 122.5 m
Calculate the final velocity using the following kinematic equation.
v = u + at
v = 0 + (9.8 m/s² × 5 s) = 49 m/s
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