A ball is dropped onto a floor from a height 20 m if you bounce to height of 5 metre if the ball is in contact with the floor for 6 milli second time the magnitude of average acceleration during that time is
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hello friend here is ur answer
, given : displacement= 20-5 = 15m
time = 6×10^-3
find,. VELOCITY
ACCELERATION
, THEN
since we know that v = s / t
follow the attachment given below
, given : displacement= 20-5 = 15m
time = 6×10^-3
find,. VELOCITY
ACCELERATION
, THEN
since we know that v = s / t
follow the attachment given below
Attachments:
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