a ball is dropped onto as floor from a height of 10m. If 20% of its energy is lost, then the height of bounce is a) 2m b) 4m c) 8m d) 6.4m
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Initial potential energy = mgh = 10mg
It bounces with 80% of initial of energy
Therefore,
(80 × 10mg / 100) = mgh’
h’ = 8 m
Height of bounce is 8 m
(c) is the correct option.
It bounces with 80% of initial of energy
Therefore,
(80 × 10mg / 100) = mgh’
h’ = 8 m
Height of bounce is 8 m
(c) is the correct option.
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