A ball is dropped two equal to zero then the top of a building the ball takes one fourth to voice fast one metre length of a sine wave some distance from the top of the building if the velocity of the ball at the top of the top under at the bottom of the board are V1 and V2 find V1 and V2find x
Answers
Answered by
0
Answer:
hi
hope this helps
Explanation:
⇒s=ut+
2
1
gt
2
3=u(0.2)+
2
1
×10×(0.2)
2
3=0.2u+0.2
0.2
2.8
=u
u=14 m/s
Answered by
0
Answer:
Explanation:
Sorry it's a very tough question
THIS IS THE ANSWER U GAVE TO MY QUESTION
NEWTON'S 3RD LAW
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