Question

A ball is dropped vertically from a height d above the ground

Answer 1

Answer:

At h=dh=d , velocity is zero,

( Taking downward direction as negative)

Then its negetive value increases , and at h=0h=0 velocity gets reversed and then goes on decreasing and becomes zero at h=d/2h=d/2

Hence a is the correct answer.

A ball is dropped vertically from a height 'd'above the ground. it hits the ground and bounces up vertically to a height d/2 neglecting air resistance its velocity 'v' varies with height 'h' above the ground as.

hope it helps ,

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Answer 2

I guess your question is incomplete...

if you wish to find the time taken by the ball in reaching the ground, you can use the second equation of motion :

$h = ut + \frac{1}{2} a {t}^{2}$

if you wish to find the maximum velocity of the ball when reaching the ground then you can use the third equation of motion:

${v}^{2} = {u}^{2} + 2as$

Given Data:

• The initial velocity (u) = 0

• The acceleration due to gravity (g) = 9.8m/s²

• The height (h) = d metres