Question

A ball is dropped vertically from rest at time t = 0 and
accelerates downwards with an acceleration g.
What distance does it travel between t = t1 and t = t2?

Answer 1

Answer:

$first \: given \: here \:$

u = 0

v = v

a = g

t = t1 – t2 ;

Now use the formula

S = ut + 1/2 g (t)²

since we know u = 0

there 0 × t = 0

hence the distance travelled =

S = 1/2 g (t)²

here is your answer with verification.