a ball is fallen from a tower.It takes 5s to reach the ground what is its height
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Answered by
2
Answer:
v=u+gt
t=5 sec
u=0
∣v∣=5g=5×9.8=49 m/s
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10
Initial velocity (u) = 0m/s
Time taken (t) = 5 seconds
Acceleration due to gravity (g) = 9.8 m/s^2
Height (h) = ??
h = ut + 1/2 gt^2
h = 0 (5) + 1/2 (9.8) (5)^2
h = 122.5 m
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Time taken (t) = 5 seconds
Acceleration due to gravity (g) = 9.8 m/s^2
Height (h) = ??
h = ut + 1/2 gt^2
h = 0 (5) + 1/2 (9.8) (5)^2
h = 122.5 m
This is your answer
Mark me as a brainlist please
Take care..
Bye..!!! ☺️☺️
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