Question

A ball is falling freely from a tower of height 5m . How much momentum does it transfer to the floor if it's mass is 500g​

Answer 1

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${v}^{2} - {u}^{2} = 2gh \\ {v}^{2} = 2 \times 10 \times 5 = 100 \: m {s}^{ - 1} \\ v = \sqrt{100} = 10m {s}^{ - 1} \\ \\ p = mv \\ p = \frac{500}{1000} \times 10 \\ p = 5 \: kgm {s}^{ - 1}$

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Answer 2

h=5m

g=10m/sec^2

m=500g=0.5kg

p=?

v^2=u^2+2gh

in free fall initial velocity is zero

v^2=0+2×10×5

v^2=100

v=√100

v=10m/sec

p=mv

p=0.5×10

p=5 kg m/sec