Question

A ball is falling from a height of 100 m. After 1 sec, it covers 5 m distance.Find The distance of ball after 4 sec ?

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Answer 1

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$\huge\bold\star\red{Given:}$

• $\purple{Distance\: travelled=5m}$
• $\purple{Time\: taken= 1 sec}$
• $\purple{Hieght= 100m}$

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$\huge\bold\star\blue{ Find: }$

${ The \:distance \: travelled \:by\: ball\: after\: 4\: sec ?}$

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$\large\mathcal\red{\underline{\overline{\mid{\green{Sollution}}\mid}}}$

$\blue{we\: know\: that \:velocity \:of\: the\: ball }$

$\blue{is \:given \:by\: the \:equation},$

$\boxed{V=\frac{distance\:travelled}{time }}$

$\boxed{v=\frac{ d}{t }}$

$➠v=\frac{ 5}{1 }$

$➠\purple{\underline{v= 5m/s}}$

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$\underline{now, }$

$\green{we \:have \:to \:calculate \: distance}$

$\green{travelled \: by \:the \: ball \:after \:4 \: sec. }$

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$v= 5m/s \:and\: t= \:4\: seconds.$

$\blue{{we \:know \:that \:distance \: travelled \: by \:an } }$

$\blue{ {object \:is \:given \:by \: the \:equation,} }$

$\boxed{distance= velocity✘time taken }$

$\boxed{d= v✘t }$

$➠d= 5✘4$

$➠\purple{\boxed{d= 20m }}$

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$\large\mathcal\red{\underline{\overline{\mid{\blue{Answer}}\mid}}}$

$Hence,\: after \:4 \:seconds \:the\: ball\: covers$

$a \:distance \:of \:20m$

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Answer 2

Given :

• Height = 100 m
• Distance travelled = 5 m
• Time taken = 1 sec

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To Find :

• Distance travelled after 4 sec

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Solution :

We know that velocity of an object is :

$\large \boxed{\bf Velocity=\frac{distance\:travelled}{time}}$

$\large \boxed{\bf v=\frac{ d}{t }}$

$\bf :\implies v = \frac{ 5}{1 }$

$\bf :\implies v = 5m/s$

$\large \boxed{\bf v = 5m/s}$

Now, to find distance travelled by ball after 4 secs, we have

• velocity, v = 5m/s
• time, t = 4 secs

We know that,

$\large \boxed{\bf distance= velocity \times time \: taken }$

$\large \boxed{\bf d= v \times t }$

$:\implies d= 5 \times 4$

$:\implies d= 20m$

$\bf{\therefore \: The \: distance \: of \: ball \: after \:4 \:seconds = 20m.}$