A ball is gently droped from a height of 20m. If the velocity increase uniformly at the rate of 10ms-2 with what velocity will it strike the ground?After what time will it striked the ground?
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Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’.
Given parameters
Initial Velocity of the ball (u) = 0
Distance or height of fall (s) = 20 m
Downward acceleration (a) = 10 m s-2
As we know
2as = v2 – u2
v2 = 2as + u2
v2 = (2 x 10 x 20 ) + 0
v2 = 400
Final velocity of ball (v) = 20 ms-1
t = (v – u)/a
Time taken by the ball to strike (t) = (20 – 0)/10
t = 20/10
t = 2 seconds
The final velocity with which ball will strike the ground is (v) = 20 ms-1
The time it takes to strike the ground (t) = 2 seconds
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