a ball is gently droped from height 20m if its velocity increases uniformly at the rate of 10ms-2 with what velocity will it strike the ground? after what time will it strike the ground
anisharra:
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please check the attached file
Time 2 sec
Velocity 20m/s
Attachments:
velocity is 20 m/s & time is 2 sec.
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Given in question,
Initial velocity = 0 m/s, height = 20 m, acceleration = 10 m/s^2
Time = ?
v^2 - u^2 = 2as (Third Equation Of Motion)
v^2 - 0^2 = 2*10*20
v^2 = 400
v = 20 m/s
v = u + at (First Equation Of Motion)
20 = 0 + 10t
10t = 20
t = 2 sec
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