A ball is gently dropped form a height of 40m. If its velocity increases uniformly at the rate of 10ms-2, with what velocity will it strike the ground? After what time will it strike the ground
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h=40m g=10m/s^2 u=0 v=? t=?
2gh=v^2-u^2
2×10×40=v^2
v=20root 2 m/sec
v=u+at
v=0+10×t
10t=20root2
t=2root2 sec
=2.828 sec
h=40m g=10m/s^2 u=0 v=? t=?
2gh=v^2-u^2
2×10×40=v^2
v=20root 2 m/sec
v=u+at
v=0+10×t
10t=20root2
t=2root2 sec
=2.828 sec
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