Question

A ball is gently dropped from a height of 20 km if it velocity increases uniformly at the rate of 10 ms with what velocity will it strike the ground? after what time will it strike the grounds ​

Answer 1

Answer:

Given that,

Distance(s)="20m"

Initial velocity(u)=0m/s

Accelaration="10m/s-2"

Using the relation Distance-Time

s=v2 - u2=2a

s= v2-0=2*10

20=v2-0=20

v2-0=20*20

v2=400(underoot)

v=20 m/s

time=v=u=at

20=0+10

20 upon 10=0+10(t)=

time= 2 secs

Explanation:

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