A ball is gently dropped from a height of 20 m . If it's increases uniformly at the rate of 10ms-², with what velocity will it strike the ground ? After what time will it strike the ground?
Answers
Answer:
height of 20 m
Explanation:
Answer:
Time taken by the ball to strike the ground is 2 seconds.
Explanation:
Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’
Initial Velocity of ball, u =0
Distance or height of fall, s =20 m
Downward acceleration, a =10 m s-2
As we know, 2as =v2-u2
v2 = 2as+ u2
= 2 x 10 x 20 + 0
= 400
Final velocity of ball, v = 20 ms-1
t = (v-u)/a
Time taken by the ball to strike = (20-0)/10
= 20/10
Time taken by the ball to strike =2 seconds
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