Question

a ball is gently dropped from a height of 20 m . if its velocity i creases uniformaly at the rate of 10 m s-2, with what velocity willit strick the ground ? after what time will it strike the ground​

Answer 1

Ello user !!!!!!!!

Here is your answer,

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Given that,

Distance(s)="20m"

Initial velocity(u)=0m/s

Accelaration="10m/s-2"

Using the relation Distance-Time

s=v2 - u2=2a

s= v2-0=2*10

20=v2-0=20

v2-0=20*20

v2=400(underoot)

v=20 m/s

time=v=u=at

20=0+10

20 upon 10=0+10(t)=

time= 2 secs

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Answer 2

Answer:

u = 0(free fall)

v=?

s=-20m

a=g=-10m/s2

v2-u2=2as

v2 - 0 = 2 (-10)(-20)

v2 = 400

v = 20

Thus, velocity =20m/s

v=u + at

20 = 0 + 10(t)

20 = 10t

t=2

Thus, time = 2s

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