Question

A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 m/s with what velocity will it strike the ground?​

Answer 1

Answer:

20m/s

Step-by-step explanation:

Given, initial velocity of ball, u=0

Final velocity of ball, v=?

Distance through which the balls falls, s=20m

Acceleration a=10ms^−2

Time of fall, t=?

We know

v2−u2=2as

or v2−0=2×10×20=400 or v=20m/s

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Answer 2

Answer:

20 m/s

Step-by-step explanation:

d = Vo * t + 1/2 *a*t^2

here d is 20 m.

rate of velocity increment (acceleration) = 10 m/s^2

Vo is initial velocity hence zero in this case.

20 = 0.5*10*t^2

t = 2 sec

now, V = Vo + a*t

hence, V= 0 + 10*2

V= 20 m/s

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