.A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 m s-2, with what velocity will it strike the ground? After what time will it strike the ground
Answers
Explanation:
Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’
Initial Velocity of ball, u =0
Distance or height of fall, s =20 m
Downward acceleration, a =10 m s-2
As we know, 2as =v2-u2
v2 = 2as+ u2
= 2 x 10 x 20 + 0
= 400
ˆ´ Final velocity of ball, v = 20 ms-1
t = (v-u)/a
ˆ´Time taken by the ball to strike = (20-0)/10
= 20/10
= 2 seconds
Answer:
S,distance=20 m
S,distance=20 ma,acceleration =10m/s^2
S,distance=20 ma,acceleration =10m/s^2v,final velocity=?
S,distance=20 ma,acceleration =10m/s^2v,final velocity=?u,initial velocity=0
S,distance=20 ma,acceleration =10m/s^2v,final velocity=?u,initial velocity=0We know that
S,distance=20 ma,acceleration =10m/s^2v,final velocity=?u,initial velocity=0We know thatv^2-u^2=2aS
S,distance=20 ma,acceleration =10m/s^2v,final velocity=?u,initial velocity=0We know thatv^2-u^2=2aSv^2-0=2×10×20
S,distance=20 ma,acceleration =10m/s^2v,final velocity=?u,initial velocity=0We know thatv^2-u^2=2aSv^2-0=2×10×20400=v^2
S,distance=20 ma,acceleration =10m/s^2v,final velocity=?u,initial velocity=0We know thatv^2-u^2=2aSv^2-0=2×10×20400=v^2v=20m/s
S,distance=20 ma,acceleration =10m/s^2v,final velocity=?u,initial velocity=0We know thatv^2-u^2=2aSv^2-0=2×10×20400=v^2v=20m/st=?
S,distance=20 ma,acceleration =10m/s^2v,final velocity=?u,initial velocity=0We know thatv^2-u^2=2aSv^2-0=2×10×20400=v^2v=20m/st=?We know that
S,distance=20 ma,acceleration =10m/s^2v,final velocity=?u,initial velocity=0We know thatv^2-u^2=2aSv^2-0=2×10×20400=v^2v=20m/st=?We know that v=u+at
S,distance=20 ma,acceleration =10m/s^2v,final velocity=?u,initial velocity=0We know thatv^2-u^2=2aSv^2-0=2×10×20400=v^2v=20m/st=?We know that v=u+at20=0+10t
S,distance=20 ma,acceleration =10m/s^2v,final velocity=?u,initial velocity=0We know thatv^2-u^2=2aSv^2-0=2×10×20400=v^2v=20m/st=?We know that v=u+at20=0+10tt=2 sec