A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 m s-2, with what velocity will it strike the ground?
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height= 20m/s
initial velocity u =0
acceleration a = 10m/s
v^2=u^2 +2as
v^2= 0+2×10×20
v^2=400
v=20 m/s
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