A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 m s -2
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with what velocity will it strike the ground? Find work done during this change?
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Answer:
u=0
v=?
s=20m
a=10ms-2
t=?
using formula
v^2-u^2=2as
v^2-2*10*20=400or v=20ms^-1
now using formula v=u plus at
20=0plus 10*t
t=2s
Explanation:
hope it was help
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