A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10m s-2 with what velocity will it strike the ground? After what time will it strike the ground?
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Answered by
2
20 m/s is the right answer
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shnayasheikh:
Its really short
Answered by
4
I will do in step by step shnayasheikh:-
Displacement=s=20m
Initial velocity=u=0
Acceleration=a=10m/s^2
Using
2as=v^2-u^2
v^2=2*10*20
v^2=20^2
final velocity =20m/s
Hope it helps u
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