Question

A ball is gently dropped from a height of 20 m. if its velocity e increase uniformly at the rate of 10 ms-² with, what velocity will it strike the ground?​

Answer 1

Hey mate here is your answer

here is step by step answer

A Given, initial velocity of ball, u=0

Final velocity of ball, v=?

Distance through which the balls falls, s=20m

Acceleration a=$10ms^{-2}$

Time of fall, t=?

We know

$v^{2} -u^{2} =2as$  

or $v^{2}$  $-0=2\times10\times20=400\or v=20ms-1$

 

Now using v=u+at we have

$20=0+10\timest\ or\ t=2s$