Question

A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 m s^-2, with what velocity will it strike the ground? After what time will it strike the ground?


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Answer 1

Answer:

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Answer 2

Explanation:

Given:-

• initial velocity = u
• final Velocity = v
• a= 10ms-²
• time taken = t
• Height from the ground = 20m

To find:-

Velocity to strike the ground.

Time taken to strike the ground.

Solution:-

Using, Third law of equation

→ v²-u² = 2as

→ v² = 2as+u²

→ v² = 2(10)(20)+0²

→ v² = 400+0

→ v² = 400

→ v = 20

Therefore, the final Velocity is 20m/s.

→ a = (v-u)/t

→ t = (v-u)/a

→ t = (20-0)/10

→ t = 20/10

→ t = 2

Therefore, the time taken to strike the ground is 2 second.