Question

A ball is gently dropped from a height of 20 m if the velocity increases uniformly @ 10m per second square with what

Answer 1

Answer :

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Answer 2

Answer:

Given that,

Distance(s)="20m"

Initial velocity(u)=0m/s

Accelaration="10m/s-2"

Using the relation Distance-Time

s=v2 - u2=2a

s= v2-0=2*10

20=v2-0=20

v2-0=20*20

v2=400(underoot)

v=20 m/s

time=v=u=at

20=0+10

20 upon 10=0+10(t)=

time= 2 secs