Physics, asked by lovingrathour, 2 months ago

A ball is gently dropped from a height of 20 m. Its velocity increases uniformly at the rate of 10 ms.
What is the final momentum of ball

Answers

Answered by dna63

We have,

initial speed of ball, u= 0 m/s

acceleration due to gravity, g = 10 m/s²

distance, s = 20 m

final speed of ball, v = ?

Let mass of ball = m

Using third equation of motion,

v² - u² = 2gs

=> v² - 0² = 2 × 10 × 20

=> v² = 400

=> v = 20 m/s

Therefore,

Final momentum of ball = m × 20 = 20m

Answered by nancynegi

Given parameters

Initial Velocity of the ball (u) = 0

Distance or height of fall (s) = 20 m

Downward acceleration (a) = 10 m s-2

As we know

2as = v2 – u2

v2 = 2as + u2

v2 = (2 x 10 x 20 ) + 0

v2 = 400

Final velocity of ball (v) = 20 ms-1

t = (v – u)/a

Time taken by the ball to strike (t) = (20 – 0)/10

t = 20/10

t = 2 seconds

The final velocity with which the ball will strike the ground is (v) = 20 ms-1

The time it takes to strike the ground (t) = 2 seconds

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