Question

A ball is gently dropped from a height of 20 m onto a hard surface where it make an elastic collision. If frictional losses are very small, it returns to its original height and continues to bounce up and down.
2) Why isn’t the acceleration at the top point of the ball zero
3) Use axes below to sketch a graph of how the velocity of the ball varies with time during several bounces

Answer 1

Answer:

ANSWER

Height, s=20m

Acceleartion , a=10m/s2

By 3rd equation of motion 

v2=u2+2as

v2=0+2×10×20=400

⇒v=20m/s

So, we conclude final velocity , v=20m/s

again, by 1st equation of motion , v=u+at

⇒t=av−u

⇒t=1020=2s

So, it will strike the ground after 2s

Explanation:

hi

hope..........