A ball is gently dropped from a height of 20 metre if its velocity increases a uniformly at the rate of 10 metre per second square with what velocity will it strike the ground after what time will it strike the ground
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t = 2 seconds
v = 20 m/s
Explanation:
s = 20m
u = 0 m/s
a = 10 m/s^2
s = u*t + 1/2 * a*t ^2
20 = 1/2 * 10 * t ^2
2 seconds = t
v = u + a*t
v = 10 * 2
= 20 m /s
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