Question

a ball is gently dropped from a height of 20m if it's velocity increases uniformly at a rate of 10m/s'2 with what velocity will it strike the ground ? after what time will it strike the ground ?

Answer 1

ʜᴇʟʟᴏ ᴍᴀᴛᴇ!

Here, s ( distance )= 20 m

a ( acceleration )= 10 m/s²

u ( initial velocity ) = 0

s = ut + 1/2 ( at² )

20 = (0)(t) + 1/2 (10)(t²)

20 = 5t²

4 = t² and t = 2s

v = u + at

v = 0 + (10)(2)

v = 20 m/s

Hope it helps

Answer 2

Bonjour!

According to the question,

Distance (s) = 20 m
Acceleration (a) = 10 m/s²
Initial velocity = 0

To find the time it will take to strike the ground, we will use the formula;

=> s = ut + 1/2at²

Putting the value---›

=> 20 = 0×t + 1/2×10×t²

=> 20 = 5t²

=> t² = 20/5

=> t² = 4

=> t = 2s

Therefore, the time will it strike the ground is 2s.

Now, for calculating the velocity will it strike the ground, we will use the formula;

=> v = u + at

Putting the value---›

=> v = 0 + 10×2

=> v = 20 m/s

Therefore, the velocity it will possess when it strikes the ground will be 20 m/s.

Hope this helps...:)