A ball is gently dropped from a height of 20m if its velocity increases uniformly at the rate of 10 metre per second square with what velocity will it strike the ground after what time will it strike the ground
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Answer:
Given ,
S = 20 m
a = 10 m/s2
U = 0
We know that ,
S = Ut + 1/2 at2
=> 20 = 0×t + 1/2 × 10 × t2
=> 20 = 5 × t2
=> 20÷5 = t2
=> t2 = 4
=> t = 2 sec
.
. . It will strike the ground
after 2 sec .
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