Question

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A ball is gently dropped from a height of 20m. If its velocity increases uniformly at the rate of 10ms² with what velocity will it stike the ground? After what time will it stirke the ground?

Plzz tell me fast

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Answer 1

Answer:

$\bold {\huge {Your ~answer :-}}$

$\bf\huge\boxed{20m/s,\:2sec}$

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Given & to find —

initial velocity of ball,u = 0

Final velocity of ball, v= ?

Distance through which the balls falls,s = 20 m

Acceleration, a = 10 m/s²

Time of fall, t =?

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We know

${v}^{2} - {u}^{2} = 2as$

$= > {v}^{2} - 0 = 2 \times 10 \times 20$

=> v = 20 m/s

Therefore velocity while strike the ground is 20 m/s

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Now for t we know

v = u + at

=> 20 = 0 + 10 t

=> t = 20/10

=> t = 2 sec

Therefore, time of fall is 2 sec

$\huge{\red{\ddot{\smile}}}$

Answer 2

Answer:

time =2sec.............