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A ball is gently dropped from a height of 20m. If its velocity increases uniformly at the rate of 10ms² with what velocity will it stike the ground? After what time will it stirke the ground?
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Answers
Answered by
6
Answer:
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Given & to find —
initial velocity of ball,u = 0
Final velocity of ball, v= ?
Distance through which the balls falls,s = 20 m
Acceleration, a = 10 m/s²
Time of fall, t =?
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We know
=> v = 20 m/s
Therefore velocity while strike the ground is 20 m/s
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Now for t we know
v = u + at
=> 20 = 0 + 10 t
=> t = 20/10
=> t = 2 sec
Therefore, time of fall is 2 sec
Answered by
7
Answer:
time =2sec.............
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