Question

A ball is gently dropped from a height of 20m. If its velocity increase uniformly at the rate of 10ms-2after what time it will strik the ground

Answer 1

Answer:

after 2s it will strike thanks

Answer 2

Initial velocity = 0 m/s, height = 20 m, acceleration = 10 m/s^2

Time = ?

v^2 - u^2 = 2as (Third Equation Of Motion)

v^2 - 0^2 = 2*10*20

v^2 = 400

v = 20 m/s

v = u + at (First Equation Of Motion)

20 = 0 + 10t

10t = 20

t = 2 sec