Question

A BALL IS GENTLY DROPPED FROM A HEIGHT OF 20m.if its velocity increases uniformly at the rate of 10ms-2,with what velocity will it.strike the ground after what time will it strike the ground

Answer 1

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Answer 2

Given that, a ball is dropped from a height of 20 m and acceleration of the ball is 10 m/s².

We have to find that with what velocity ball will strike the ground after what time will it strike the ground.

From above data we have height (s) = 20 m, acceleration (a) = 10 m/s² and initial velocity of the ball (u) = 0 m/s

Using the Third Equation Of Motion,

v² - u² = 2as

Substitute the known values,

v² - (0)² = 2(10)(20)

v² = 400

v = √400

v = 20

Therefore, the velocity of the ball is 20 m/s with which it strike the ground.

Now, using the Second Equation Of Motion,

s = ut + 1/2 at²

Substitute value of s = 20 m, u = 0 m/s and a = 10 m/s² in the above formula,

20 = 0(t) + 1/2 × 10 × t²

20 = 0 + 5t²

20 = 5t²

20/5 = t²

4 = t²

(2)² = t²

2 = t

Therefore, the time taken by the ball is 2 sec with which it strike the ground.