Question

A ball is gently dropped from a height of 20m. If its velocity​

Answer 1

Answer:

provide full question correctly

Answer 2

initial velocity,u=0 (dopped gently)

acceleration,a=10m/s2

height,s=20m

final velocity,v=?

time taken ,t=?

Use third equation of motion:

v2(square)=u2(square)+2as

v2(square)=0+2×10×20

v2(square)=400

v=20m/s

using second equation of motion:

s=ut+1/2at2(square)

20=0×t+1/2×10×t2(square)

t2(square)=4

t=2s