Question

A ball is gently dropped from a height of 20m.If its velocity increases uniformly at the rate of 10m/s²,with what velocity will it strike the ground?after what time will it strike the ground?​

Answer 1

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Given that,

Distance(s)="20m"

Initial velocity(u)=0m/s

Accelaration="10m/s-2"

Using the relation Distance-Time

s=v2 - u2=2a

s= v2-0=2*10

20=v2-0=20

v2-0=20*20

v2=400(underoot)

v=20 m/s

time=v=u=at

20=0+10

20 upon 10=0+10(t)=

time= 2 secs

Answer 2

Answer:

Hey ,,

answer is ...

v= 20m/s

T= 2 sec

thank you ...

have a good day