A ball is gently dropped from a height of 20m. If its velocity increases uniformly at the rate of 10 m s-2 , with what velocity will it strike the ground ? After what time will it strike the ground
Answers
Answered by
0
Explanation:
here intial velocity
is 10mper second squre
then final velocity=?
so,2as=v2-u2
v2=2as+u2
v2=2×20×10+0
v2=400
v=20
niw time =?
t=v-u/t
20-0/10
=2sec
hope it may help u
Similar questions