A ball is gently dropped from a height of 20m if its velocity increases uniformly at the rate of 10 ms^-2 , with that velocity with what velocity will it strike the ground? after what time will it strike the ground?
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here, U (initial velocity)= 0
V ^2 = U ^2 + 2as
= 0 + 2*10*20
= 400
V = √400 = 20 m/s ans.
Now,
V = u + at
20 = 0 + 10 t
20 = 10t
20/10 = t
t = 2 seconds..
V ^2 = U ^2 + 2as
= 0 + 2*10*20
= 400
V = √400 = 20 m/s ans.
Now,
V = u + at
20 = 0 + 10 t
20 = 10t
20/10 = t
t = 2 seconds..
UdbhavAshish:
thanx
:-)
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