A ball is gently dropped from a height of 20m. If the velocity increases uniformly at the rate of 10 meter per second square, with what velocity will it strike the ground? After what time will it strike the ground?
Answers
Answered by
2
Answer:
Let us assume, the final velocity with which the ball will strike the ground be ‘v’ and the time it takes to strike the ground be ‘t’.
Given parameters
- Initial Velocity of the ball (u) = 0
- Distance or height of fall (s) = 20 m
- Downward acceleration (a) = 10 m s-2
As we know
★ 2as = v2 – u2
⟼ v2 = 2as + u2
⟼ v2 = (2 x 10 x 20 ) + 0
⟼ v2 = 400
Final velocity of ball (v) = 20 ms-1
★ t = (v – u)/a
Time taken by the ball to strike (t) = (20 – 0)/10
⟼ t = 20/10
⟼ t = 2 seconds
- The final velocity with which the ball will strike the ground is (v) = 20 ms-1
- The time it takes to strike the ground (t) = 2 seconds
Similar questions